Address-of-operator in C++

Address-of operator (&) accepts a lvalue and returns a pointer object whose value is the address of that lvalue.

We can use address-of operator as shown below:

int value{100};
 
std::cout << &value;

So, &value returns pointer object int* and printing &value prints the address of value variable.

If we check the type of &value, we should see something like below:

#include <iostream>
#include <typeinfo>
 
int main(int argc, char const *argv[])
{
    int value{100};
    std::cout << &value << "\n";
 
    std::cout << typeid(value).name() << "\n";
    std::cout << typeid(&value).name() << "\n";
    return 0;
}

0x30a284aec
i
Pi

where i is int type for variable value and Pi is Pointer to int.

References

1. https://www.learncpp.com/cpp-tutorial/introduction-to-pointers/